{"id":12695,"date":"2023-02-13T01:51:33","date_gmt":"2023-02-12T16:51:33","guid":{"rendered":"https:\/\/hatsudy.com\/jp\/?p=12695"},"modified":"2023-02-24T03:03:30","modified_gmt":"2023-02-23T18:03:30","slug":"function-2","status":"publish","type":"post","link":"https:\/\/hatsudy.com\/jp\/function-2.html","title":{"rendered":"\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\uff1a\u516c\u5f0f\u3001\u7f6e\u304d\u63db\u3048\u3001\u306f\u3055\u307f\u3046\u3061\u306e\u539f\u7406\u3067\u306e\u8a08\u7b97"},"content":{"rendered":"\n<p>\u95a2\u6570\u306e\u6975\u9650\u3092\u8a08\u7b97\u3059\u308b\u3068\u304d\u3001\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u3092\u8a08\u7b97\u3057\u306a\u3051\u308c\u3070\u3044\u3051\u306a\u3044\u3053\u3068\u304c\u3042\u308a\u307e\u3059\u3002\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u306e\u8a08\u7b97\u3067\u306f\u3001\u516c\u5f0f\u3092\u5229\u7528\u3057\u307e\u3057\u3087\u3046\u3002\u516c\u5f0f\u3092\u5229\u7528\u3067\u304d\u306a\u3044\u5834\u5408\u3067\u3042\u3063\u3066\u3082\u3001\u5f0f\u3092\u5909\u5f62\u3059\u308b\u3053\u3068\u306b\u3088\u3063\u3066\u516c\u5f0f\u3092\u5229\u7528\u3067\u304d\u308b\u3088\u3046\u306b\u3059\u308b\u5fc5\u8981\u304c\u3042\u308a\u307e\u3059\u3002<\/p>\n<p>\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u306b\u95a2\u3059\u308b\u516c\u5f0f\u306f\u899a\u3048\u306a\u3051\u308c\u3070\u3044\u3051\u307e\u305b\u3093\u3002\u305d\u306e\u3064\u3069\u3001\u8a3c\u660e\u3092\u3059\u308b\u3068\u6642\u9593\u304c\u304b\u304b\u308b\u304b\u3089\u3067\u3059\u3002\u305f\u3060\u3001\u3069\u306e\u3088\u3046\u306b\u3057\u3066\u516c\u5f0f\u3092\u5f97\u308b\u306e\u304b\u7406\u89e3\u3057\u307e\u3057\u3087\u3046\u3002<\/p>\n<p>\u307e\u305f\u3001\u516c\u5f0f\u3092\u5229\u7528\u3059\u308b\u3053\u3068\u3067\u8a08\u7b97\u554f\u984c\u3092\u89e3\u3051\u308b\u3088\u3046\u306b\u306a\u3089\u306a\u3051\u308c\u3070\u3044\u3051\u307e\u305b\u3093\u3002\u305d\u3053\u3067\u5f0f\u3092\u5909\u5f62\u3057\u305f\u308a\u3001\u7f6e\u304d\u63db\u3048\u3092\u5229\u7528\u3057\u305f\u308a\u3059\u308b\u3053\u3068\u3067\u7b54\u3048\u3092\u5f97\u307e\u3057\u3087\u3046\u3002<\/p>\n<p>\u305d\u308c\u3067\u306f\u3001\u3069\u306e\u3088\u3046\u306b\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u306e\u554f\u984c\u3092\u89e3\u3051\u3070\u3044\u3044\u306e\u3067\u3057\u3087\u3046\u304b\u3002\u516c\u5f0f\u306e\u8a3c\u660e\u3084\u5229\u7528\u6cd5\u3092\u89e3\u8aac\u3057\u3066\u3044\u304d\u307e\u3059\u3002<\/p>\n<h2>\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u3067\u5229\u7528\u3055\u308c\u308b\u516c\u5f0f<\/h2>\n<p>\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u3092\u8a08\u7b97\u3059\u308b\u3068\u304d\u3001\\(\\displaystyle \\lim_{ x \\to 0 } sin\\ x=0\\)\u3084\\(\\displaystyle \\lim_{ x \\to 0 } cos\\ x=1\\)\u306f\u5bb9\u6613\u306b\u7406\u89e3\u3067\u304d\u307e\u3059\u3002\u305d\u308c\u3067\u306f\u3001\\(\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{sin\\ 2x}{x}\\)\u306f\u3069\u306e\u3088\u3046\u306b\u8a08\u7b97\u3059\u308c\u3070\u3044\u3044\u306e\u3067\u3057\u3087\u3046\u304b\u3002<\/p>\n<p>\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u3067\u306f\u516c\u5f0f\u304c\u3042\u308a\u3001\u4ee5\u4e0b\u306e\u516c\u5f0f\u3092\u5229\u7528\u3057\u307e\u3059\u3002<\/p>\n<ul>\n<li>\\(\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{sin\\ x}{x}=1\\)<\/li>\n<li>\\(\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{x}{sin\\ x}=1\\)<\/li>\n<\/ul>\n<p>\u3053\u306e\u516c\u5f0f\u3092\u5229\u7528\u3059\u308c\u3070\u3001\u4ee5\u4e0b\u306e\u3088\u3046\u306b\u8a08\u7b97\u3067\u304d\u307e\u3059\u3002<\/p>\n<p>\\(\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{sin\\ 2x}{x}\\)<\/p>\n<p>\\(=\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{sin\\ 2x}{2x}\u00b72\\)<\/p>\n<p>\\(=1\u00d72\\)<\/p>\n<p>\\(=2\\)<\/p>\n<p>\u3053\u3046\u3057\u3066\u3001\u7b54\u3048\u3092\u5f97\u308b\u3053\u3068\u304c\u3067\u304d\u307e\u3057\u305f\u3002<\/p>\n<h3>\u516c\u5f0f\u306e\u8a3c\u660e\u3092\u884c\u3046<\/h3>\n<p>\u305d\u308c\u3067\u306f\u3001\u306a\u305c\u5148\u307b\u3069\u8a18\u3057\u305f\u516c\u5f0f\u304c\u6210\u308a\u7acb\u3064\u306e\u3067\u3057\u3087\u3046\u304b\u3002\u516c\u5f0f\u306e\u8a3c\u660e\u3092\u3057\u307e\u3057\u3087\u3046\u3002\u307e\u305a\u3001\u4ee5\u4e0b\u306e\u3088\u3046\u306b\u4e8c\u7b49\u8fba\u4e09\u89d2\u5f62\u3067\u3042\u308b\u25b3OAB\u3068\u6247\u5f62OAB\u3092\u4f5c\u308a\u307e\u3059\u3002<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/hatsudy.com\/jp\/wp-content\/uploads\/2023\/02\/pgje6.jpg\" alt=\"\" width=\"372\" height=\"282\" class=\"aligncenter size-full wp-image-12709\" \/><\/p>\n<p>\u25b3OAB\u306e\u9762\u7a4d\u306f\\(\\displaystyle\\frac{1}{2}\u00d71\u00d71\u00d7sin\\ x=\\displaystyle\\frac{sin\\ x}{2}\\)\u3067\u3059\u3002\u305d\u308c\u3067\u306f\u3001\u6247\u5f62OAB\u306e\u9762\u7a4d\u306f\u3044\u304f\u3089\u3067\u3057\u3087\u3046\u304b\u3002\u6247\u5f62\u306e\u9762\u7a4d\u306f\u534a\u5f84\\(r\\)\u3068\u4e2d\u5fc3\u89d2\\(\u03b8\\)\u3067\u6c7a\u307e\u308a\u307e\u3059\u3002\\(r^2\u00d7\\displaystyle\\frac{\u03b8}{360}\\)\u304c\u6247\u5f62\u306e\u9762\u7a4d\u306b\u306a\u308a\u307e\u3059\u304c\u3001\u89d2\u5ea6\u304c\u5f27\u5ea6\u6cd5\u306e\u5834\u5408\u3001\\(r^2\u00d7\\displaystyle\\frac{\u03b8}{2}\\)\u304c\u6247\u5f62\u306e\u9762\u7a4d\u3067\u3059\u3002<\/p>\n<p>\u305d\u306e\u305f\u3081\u5f27\u5ea6\u6cd5\u3092\u5229\u7528\u3059\u308b\u3068\u3001\u4e0a\u56f3\u3067\u306e\u6247\u5f62\u306e\u9762\u7a4d\u306f\\(1^2\u00d7\\displaystyle\\frac{x}{2}=\\displaystyle\\frac{x}{2}\\)\u3067\u3059\u3002\u25b3<span>OAB<\/span>\u306e\u9762\u7a4d\u3088\u308a\u3082\u6247\u5f62\u306e\u9762\u7a4d\u306e\u307b\u3046\u304c\u5927\u304d\u3044\u305f\u3081\u3001\u4ee5\u4e0b\u306e\u95a2\u4fc2\u304c\u6210\u308a\u7acb\u3061\u307e\u3059\u3002<\/p>\n<ul>\n<li>\\(\\displaystyle\\frac{sin\\ x}{2}&lt;\\displaystyle\\frac{x}{2}\\)<\/li>\n<\/ul>\n<p>\u6b21\u306b\u3001\u4ee5\u4e0b\u306e\u56f3\u5f62\u3092\u4f5c\u308a\u307e\u3057\u3087\u3046\u3002<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/hatsudy.com\/jp\/wp-content\/uploads\/2023\/02\/pgje7.jpg\" alt=\"\" width=\"373\" height=\"316\" class=\"aligncenter size-full wp-image-12710\" \/><\/p>\n<p>\u8fbaAT\u306e\u9577\u3055\u306f\\(tanx\\)\u3067\u3042\u308b\u305f\u3081\u3001\u25b3OAT\u306e\u9762\u7a4d\u306f\\(\\displaystyle\\frac{tanx}{2}\\)\u3067\u3059\u3002\u6247\u5f62\u306e\u9762\u7a4d\u3088\u308a\u3082\u25b3OAT\u306e\u9762\u7a4d\u306e\u307b\u3046\u304c\u5927\u304d\u3044\u305f\u3081\u3001\u4ee5\u4e0b\u306e\u95a2\u4fc2\u5f0f\u3092\u4f5c\u308a\u307e\u3057\u3087\u3046\u3002<\/p>\n<ul>\n<li>\\(\\displaystyle\\frac{sin\\ x}{2}&lt;\\displaystyle\\frac{x}{2}&lt;\\displaystyle\\frac{tanx}{2}\\)<\/li>\n<\/ul>\n<p>\u305d\u3053\u3067\u3001\u4ee5\u4e0b\u306e\u3088\u3046\u306b\u5f0f\u3092\u5909\u5f62\u3057\u307e\u3059\u3002<\/p>\n<p>\\(\\displaystyle\\frac{sin\\ x}{2}&lt;\\displaystyle\\frac{x}{2}&lt;\\displaystyle\\frac{tanx}{2}\\)<\/p>\n<p>\\(sin\\ x&lt;x&lt;tanx\\)<\/p>\n<p>\\(\\displaystyle\\frac{1}{tanx}&lt;\\displaystyle\\frac{1}{x}&lt;\\displaystyle\\frac{1}{sin\\ x}\\)<\/p>\n<p>\\(\\displaystyle\\frac{sin\\ x}{tanx}&lt;\\displaystyle\\frac{sin\\ x}{x}&lt;\\displaystyle\\frac{sin\\ x}{sin\\ x}\\)<\/p>\n<p>\\(cosx&lt;\\displaystyle\\frac{sin\\ x}{x}&lt;1\\)<\/p>\n<p>\\(\\displaystyle \\lim_{ x \\to 0 } cosx=1\\)\u3067\u3042\u308b\u305f\u3081\u3001\u306f\u3055\u307f\u3046\u3061\u306e\u539f\u7406\u3088\u308a\u3001\\(\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{sin\\ x}{x}=1\\)\u3067\u3059\u3002\u3053\u3046\u3057\u3066\u3001\u516c\u5f0f\u3092\u8a3c\u660e\u3067\u304d\u307e\u3057\u305f\u3002<\/p>\n<p><strong>\u30fb\\(\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{x}{sin\\ x}=1\\)\u3092\u5f97\u308b<\/strong><\/p>\n<p>\u306a\u304a\u3001\u5148\u307b\u3069\u8a08\u7b97\u3057\u305f\u516c\u5f0f\u3092\u5229\u7528\u3057\u3066\\(\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{x}{sin\\ x}=1\\)\u3068\u306a\u308b\u3053\u3068\u3092\u8a3c\u660e\u3057\u307e\u3057\u3087\u3046\u3002\u4ee5\u4e0b\u306e\u3088\u3046\u306b\u5f0f\u3092\u5909\u5f62\u3057\u307e\u3059\u3002<\/p>\n<p>\\(\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{x}{sin\\ x}\\)<\/p>\n<p>\\(=\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{1}{\\displaystyle\\frac{sin\\ x}{x}}\\)<\/p>\n<p>\\(=\\displaystyle\\frac{1}{1}\\)<\/p>\n<p>\\(=1\\)<\/p>\n<p>\u3053\u3046\u3057\u3066\u3001\\(\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{x}{sin\\ x}=1\\)\u306b\u306a\u308b\u3068\u308f\u304b\u308a\u307e\u3057\u305f\u3002<\/p>\n<h2>\u516c\u5f0f\u3092\u5229\u7528\u3057\u3066\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u3092\u8a08\u7b97\u3059\u308b<\/h2>\n<p>\u305d\u308c\u3067\u306f\u3001\u5148\u307b\u3069\u8a3c\u660e\u3057\u305f\u516c\u5f0f\u3092\u5229\u7528\u3057\u3066\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u3092\u8a08\u7b97\u3057\u307e\u3057\u3087\u3046\u3002\u4ee5\u4e0b\u306e\u554f\u984c\u306e\u7b54\u3048\u306f\u4f55\u3067\u3057\u3087\u3046\u304b\u3002<\/p>\n<ul>\n<li>\\(\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{tan\\ x}{x}\\)<\/li>\n<\/ul>\n<p>\u4ee5\u4e0b\u306e\u3088\u3046\u306b\u8a08\u7b97\u3057\u307e\u3057\u3087\u3046\u3002<\/p>\n<p>\\(\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{tan\\ x}{x}\\)<\/p>\n<p>\\(=\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{sin\\ x}{x}\u00b7\\displaystyle\\frac{1}{cos\\ x}\\)<\/p>\n<p>\\(=1\u00d7\\displaystyle\\frac{1}{1}\\)<\/p>\n<p>\\(=1\\)<\/p>\n<p>\u307e\u305f\u3001\u6b21\u306e\u554f\u984c\u306e\u7b54\u3048\u306f\u4f55\u3067\u3057\u3087\u3046\u304b\u3002<\/p>\n<ul>\n<li>\\(\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{1-cos\\ x}{x^2}\\)<\/li>\n<\/ul>\n<p>\u4ee5\u4e0b\u306e\u3088\u3046\u306b\u8a08\u7b97\u3057\u307e\u3057\u3087\u3046\u3002<\/p>\n<p>\\(\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{1-cos\\ x}{x^2}\\)<\/p>\n<p>\\(=\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{1-cos\\ x}{x^2}\u00b7\\displaystyle\\frac{1+cos\\ x}{1+cos\\ x}\\)<\/p>\n<p>\\(=\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{1-cos^2\\ x}{x^2}\u00b7\\displaystyle\\frac{1}{1+cos\\ x}\\)<\/p>\n<p>\\(=\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{sin^2\\ x}{x^2}\u00b7\\displaystyle\\frac{1}{1+cos\\ x}\\)<\/p>\n<p>\\(=1\u00d7\\displaystyle\\frac{1}{1+1}\\)<\/p>\n<p>\\(=\\displaystyle\\frac{1}{2}\\)<\/p>\n<p>\u3053\u3046\u3057\u3066\u3001\u516c\u5f0f\u3092\u5229\u7528\u3059\u308b\u3053\u3068\u3067\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u3092\u8a08\u7b97\u3067\u304d\u307e\u3057\u305f\u3002<\/p>\n<h3>\u7f6e\u304d\u63db\u3048\u30fb\u306f\u3055\u307f\u3046\u3061\u306e\u539f\u7406\u3092\u5229\u7528\u3059\u308b\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u306e\u8a08\u7b97<\/h3>\n<p>\u4e00\u898b\u3059\u308b\u3068\u5148\u307b\u3069\u8a3c\u660e\u3057\u305f\u516c\u5f0f\u3092\u5229\u7528\u3067\u304d\u306a\u3044\u30b1\u30fc\u30b9\u304c\u3042\u308a\u307e\u3059\u3002\u3053\u306e\u5834\u5408\u3001\u7f6e\u304d\u63db\u3048\u3092\u5229\u7528\u3059\u308b\u3053\u3068\u3067\u516c\u5f0f\u3092\u5229\u7528\u3067\u304d\u308b\u3088\u3046\u306b\u3057\u307e\u3057\u3087\u3046\u3002\u3064\u307e\u308a\u3001<span style=\"color: #0000ff;\">\u4f55\u3068\u304b\u3057\u3066\\(\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{sin\\ x}{x}=1\\)\u3092\u4f7f\u3046\u306e\u3067\u3059\u3002<\/span><\/p>\n<p>\u7df4\u7fd2\u554f\u984c\u3068\u3057\u3066\u4ee5\u4e0b\u306e\u554f\u984c\u3092\u89e3\u304d\u307e\u3057\u3087\u3046\u3002<\/p>\n<ol>\n<li>\\(\\displaystyle \\lim_{ x \\to 1 } \\displaystyle\\frac{sin\\ \u03c0x}{x-1}\\)<\/li>\n<li>\\(\\displaystyle \\lim_{ x \\to \\frac{\u03c0}{2} } \\displaystyle\\frac{cos\\ x}{2x-\u03c0}\\)<\/li>\n<li>\\(\\displaystyle \\lim_{ x \\to \u221e } xsin\\displaystyle\\frac{1}{x}\\)<\/li>\n<li>\\(\\displaystyle \\lim_{ x \\to 0 } x^2sin\\displaystyle\\frac{1}{x}\\)<\/li>\n<\/ol>\n<p>\u306a\u304a\u5834\u5408\u306b\u3088\u3063\u3066\u306f\u3001\u516c\u5f0f\u3092\u5229\u7528\u305b\u305a\u3001\u306f\u3055\u307f\u3046\u3061\u306e\u539f\u7406\u3092\u5229\u7528\u3059\u308b\u3053\u3068\u3067\u554f\u984c\u3092\u89e3\u304b\u306a\u3051\u308c\u3070\u3044\u3051\u306a\u3044\u3053\u3068\u3082\u3042\u308a\u307e\u3059\u3002<\/p>\n<p><strong>1) \\(\\displaystyle \\lim_{ x \\to 1 } \\displaystyle\\frac{sin\\ \u03c0x}{x-1}\\)<\/strong><\/p>\n<p>\\(x \\to 0\\)\u3067\u306f\u306a\u304f\u3001\\(x \\to 1\\)\u3068\u306a\u3063\u3066\u3044\u307e\u3059\u3002\u3053\u306e\u5834\u5408\u3001\\(t=x-1\\)\u3068\u3059\u308b\u3068\u3001\\(x \\to 1\\)\u306e\u3068\u304d\u306b\\(t \\to 0\\)\u3068\u306a\u308a\u307e\u3059\u3002\u306a\u304a\\(x=t+1\\)\u3067\u3042\u308b\u305f\u3081\u3001\u4ee5\u4e0b\u306e\u3088\u3046\u306b\u8a08\u7b97\u3057\u307e\u3057\u3087\u3046\u3002<\/p>\n<p>\\(\\displaystyle \\lim_{ x \\to 1 } \\displaystyle\\frac{sin\\ \u03c0x}{x-1}\\)<\/p>\n<p>\\(=\\displaystyle \\lim_{ t \\to 0 } \\displaystyle\\frac{sin\\ \u03c0(t+1)}{(t+1)-1}\\)<\/p>\n<p>\\(=\\displaystyle \\lim_{ t \\to 0 } \\displaystyle\\frac{sin\\ (\u03c0t+\u03c0)}{t}\\)<\/p>\n<p>\\(=\\displaystyle \\lim_{ t \\to 0 } \\displaystyle\\frac{-sin\\ \u03c0t}{t}\\)<\/p>\n<p>\\(=\\displaystyle \\lim_{ t \\to 0 } \\displaystyle\\frac{sin\\ \u03c0t}{\u03c0t}\u00b7-\u03c0\\)<\/p>\n<p>\\(=-\u03c0\\)<\/p>\n<p><strong>2) \\(\\displaystyle \\lim_{ x \\to \\frac{\u03c0}{2} } \\displaystyle\\frac{cos\\ x}{2x-\u03c0}\\)<\/strong><\/p>\n<p>\u5148\u307b\u3069\u3068\u540c\u69d8\u306b\u8003\u3048\u3066\u8a08\u7b97\u3057\u307e\u3057\u3087\u3046\u3002\\(t=x-\\displaystyle\\frac{\u03c0}{2}\\)\u3068\u3059\u308b\u3068\u3001\\(x \\to \\displaystyle\\frac{\u03c0}{2}\\)\u306b\u3088\u3063\u3066\\(t \\to 0\\)\u306b\u306a\u308a\u307e\u3059\u3002\u307e\u305f\u3001\\(x=t+\\displaystyle\\frac{\u03c0}{2}\\)\u3067\u3059\u3002<\/p>\n<p>\\(\\displaystyle \\lim_{ x \\to \\frac{\u03c0}{2} } \\displaystyle\\frac{cos\\ x}{2x-\u03c0}\\)<\/p>\n<p>\\(=\\displaystyle \\lim_{ t \\to 0 } \\displaystyle\\frac{cos\\ \\left(t+\\displaystyle\\frac{\u03c0}{2}\\right)}{2t}\\)<\/p>\n<p>\\(=\\displaystyle \\lim_{ t \\to 0 } \\displaystyle\\frac{-sin\\ t}{2t}\\)<\/p>\n<p>\\(=\\displaystyle \\lim_{ t \\to 0 } \\displaystyle\\frac{sin\\ t}{t}\u00b7-\\displaystyle\\frac{1}{2}\\)<\/p>\n<p>\\(=-\\displaystyle\\frac{1}{2}\\)<\/p>\n<p><strong>3) \\(\\displaystyle \\lim_{ x \\to \u221e } xsin\\displaystyle\\frac{1}{x}\\)<\/strong><\/p>\n<p>\\(t=\\displaystyle\\frac{1}{x}\\)\u3068\u3059\u308b\u3068\u3001\\(x \\to \u221e\\)\u306e\u3068\u304d\u3001\\(t \\to 0\\)\u3068\u306a\u308a\u307e\u3059\u3002\u305d\u306e\u305f\u3081\u3001\u4ee5\u4e0b\u306e\u3088\u3046\u306b\u5f0f\u3092\u5909\u5f62\u3067\u304d\u307e\u3059\u3002<\/p>\n<p>\\(\\displaystyle \\lim_{ x \\to \u221e } xsin\\displaystyle\\frac{1}{x}\\)<\/p>\n<p>\\(=\\displaystyle \\lim_{ t \\to 0 } \\displaystyle\\frac{sin\\ t}{t}\\)<\/p>\n<p>\\(=1\\)<\/p>\n<p><strong>4) \\(\\displaystyle \\lim_{ x \\to 0 } x^2sin\\displaystyle\\frac{1}{x}\\)<\/strong><\/p>\n<p>\u3053\u3053\u307e\u3067\u3001\u516c\u5f0f\u3092\u5229\u7528\u3059\u308b\u3053\u3068\u306b\u3088\u3063\u3066\u7b54\u3048\u3092\u5f97\u3089\u308c\u308b\u5f0f\u3092\u89e3\u8aac\u3057\u3066\u304d\u307e\u3057\u305f\u3002\u305f\u3060\u5834\u5408\u306b\u3088\u3063\u3066\u306f\u3001\u516c\u5f0f\u3092\u5229\u7528\u3057\u3066\u3082\u7b54\u3048\u3092\u5f97\u3089\u308c\u306a\u3044\u30b1\u30fc\u30b9\u304c\u3042\u308a\u307e\u3059\u3002\u3053\u306e\u5834\u5408\u3001\u306f\u3055\u307f\u3046\u3061\u306e\u539f\u7406\u3092\u5229\u7528\u3059\u308b\u3053\u3068\u3067\u8a08\u7b97\u3059\u308b\u3053\u3068\u3092\u8003\u3048\u307e\u3057\u3087\u3046\u3002<\/p>\n<p>\\(-1\u2266sin\\displaystyle\\frac{1}{x}\u22661\\)\u3067\u3059\u3002\u307e\u305f\\(x\u22600\\)\u3067\u3042\u308b\u305f\u3081\u3001\u4ee5\u4e0b\u306e\u3088\u3046\u306b\u8a08\u7b97\u3057\u307e\u3057\u3087\u3046\u3002<\/p>\n<p>\\(-1\u2266sin\\displaystyle\\frac{1}{x}\u22661\\)<\/p>\n<p>\\(-x^2\u2266x^2sin\\displaystyle\\frac{1}{x}\u2266x^2\\)<\/p>\n<p>\\(\\displaystyle \\lim_{ x \\to 0 } -x^2=0\\)\u3067\u3042\u308a\u3001\\(\\displaystyle \\lim_{ x \\to 0 } x^2=0\\)\u3067\u3059\u3002\u305d\u306e\u305f\u3081\u3001\u306f\u3055\u307f\u3046\u3061\u306e\u539f\u7406\u3088\u308a\\(\\displaystyle \\lim_{ x \\to 0 } x^2sin\\displaystyle\\frac{1}{x}=0\\)\u3067\u3059\u3002<\/p>\n<h2>\u516c\u5f0f\u3092\u5229\u7528\u3057\u3066\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u3092\u5f97\u308b<\/h2>\n<p>\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u3092\u8a08\u7b97\u3059\u308b\u3068\u304d\u3001\u516c\u5f0f\u3092\u5229\u7528\u3057\u306a\u3051\u308c\u3070\u8a08\u7b97\u3067\u304d\u306a\u3044\u30b1\u30fc\u30b9\u304c\u591a\u3044\u3067\u3059\u3002\u305d\u3053\u3067\u3001\u516c\u5f0f\u3092\u899a\u3048\u307e\u3057\u3087\u3046\u3002\u3053\u306e\u3068\u304d\u3001\u516c\u5f0f\u306e\u8a3c\u660e\u3092\u884c\u3048\u308b\u3088\u3046\u306b\u306a\u308b\u3068\u3044\u3044\u3067\u3059\u3002<\/p>\n<p>\u5b9f\u969b\u306b\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u3092\u8a08\u7b97\u3059\u308b\u3068\u304d\u3001\u5f0f\u3092\u5909\u5f62\u3057\u307e\u3057\u3087\u3046\u3002\u5f0f\u3092\u5909\u3048\u305f\u308a\u3001\u7f6e\u304d\u63db\u3048\u3092\u5229\u7528\u3057\u305f\u308a\u3059\u308b\u3053\u3068\u306b\u3088\u308a\u3001\\(\\displaystyle \\lim_{ x \\to 0 } \\displaystyle\\frac{sin\\ x}{x}=1\\)\u3092\u4f7f\u3048\u308b\u3088\u3046\u306b\u3059\u308b\u306e\u3067\u3059\u3002<\/p>\n<p>\u306a\u304a\u5834\u5408\u306b\u3088\u3063\u3066\u306f\u3001\u516c\u5f0f\u3092\u5229\u7528\u305b\u305a\u307b\u304b\u306e\u65b9\u6cd5\u306b\u3088\u3063\u3066\u7b54\u3048\u3092\u5f97\u308b\u30b1\u30fc\u30b9\u3082\u3042\u308a\u307e\u3059\u3002\u516c\u5f0f\u3092\u5229\u7528\u3067\u304d\u306a\u3044\u5834\u5408\u3001\u306f\u3055\u307f\u3046\u3061\u306e\u539f\u7406\u3092\u5229\u7528\u3059\u308b\u306a\u3069\u3001\u307b\u304b\u306e\u65b9\u6cd5\u3092\u691c\u8a0e\u3057\u307e\u3057\u3087\u3046\u3002<\/p>\n<p>\u516c\u5f0f\u3092\u899a\u3048\u308b\u5fc5\u8981\u306f\u3042\u308b\u3082\u306e\u306e\u3001\u516c\u5f0f\u3092\u5229\u7528\u3059\u308c\u3070\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u3092\u8a08\u7b97\u3067\u304d\u308b\u30b1\u30fc\u30b9\u304c\u591a\u3044\u3067\u3059\u3002\u305d\u3053\u3067\u516c\u5f0f\u3092\u7528\u3044\u3066\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u3092\u5f97\u308b\u3088\u3046\u306b\u3057\u307e\u3057\u3087\u3046\u3002<\/p>\n","protected":false},"excerpt":{"rendered":"<p>\u95a2\u6570\u306e\u6975\u9650\u3092\u8a08\u7b97\u3059\u308b\u3068\u304d\u3001\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u3092\u8a08\u7b97\u3057\u306a\u3051\u308c\u3070\u3044\u3051\u306a\u3044\u3053\u3068\u304c\u3042\u308a\u307e\u3059\u3002\u4e09\u89d2\u95a2\u6570\u306e\u6975\u9650\u306e\u8a08\u7b97\u3067\u306f\u3001\u516c\u5f0f\u3092\u5229\u7528\u3057\u307e\u3057\u3087\u3046\u3002\u516c\u5f0f\u3092\u5229\u7528\u3067\u304d\u306a\u3044\u5834\u5408\u3067\u3042\u3063\u3066\u3082\u3001\u5f0f\u3092\u5909\u5f62\u3059\u308b\u3053\u3068\u306b\u3088\u3063\u3066\u516c\u5f0f\u3092\u5229\u7528\u3067\u304d\u308b\u3088\u3046\u306b\u3059\u308b\u5fc5\u8981\u304c\u3042 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":12718,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[13],"tags":[],"class_list":{"0":"post-12695","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-h-math"},"_links":{"self":[{"href":"https:\/\/hatsudy.com\/jp\/wp-json\/wp\/v2\/posts\/12695","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/hatsudy.com\/jp\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/hatsudy.com\/jp\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/hatsudy.com\/jp\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/hatsudy.com\/jp\/wp-json\/wp\/v2\/comments?post=12695"}],"version-history":[{"count":11,"href":"https:\/\/hatsudy.com\/jp\/wp-json\/wp\/v2\/posts\/12695\/revisions"}],"predecessor-version":[{"id":12759,"href":"https:\/\/hatsudy.com\/jp\/wp-json\/wp\/v2\/posts\/12695\/revisions\/12759"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/hatsudy.com\/jp\/wp-json\/wp\/v2\/media\/12718"}],"wp:attachment":[{"href":"https:\/\/hatsudy.com\/jp\/wp-json\/wp\/v2\/media?parent=12695"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/hatsudy.com\/jp\/wp-json\/wp\/v2\/categories?post=12695"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/hatsudy.com\/jp\/wp-json\/wp\/v2\/tags?post=12695"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}